• spongebue@lemmy.world
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    1 day ago

    x = -i;

    Do many languages let you do that? When it’s in front of a variable I would’ve expected it to be a subtraction operator only and you would need to do x = -1 * i;

      • squaresinger@lemmy.world
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        7 hours ago

        Nope, it is not.

        x = 5
        i = 2
        x -= i // x => 3
        

        while

        x = 5
        i = 2
        x = -i // x => -2
        

        x=-i is the unary minus operator which negates the value right of it. It doesn’t matter if that value is a literal (-3), a variable (-i) or a function (-f()).

        x-=i is short for x = x-i, and here it’s a binary subtraction, so x is set to the result of i subtracted from x.

      • spongebue@lemmy.world
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        12 hours ago

        That only works if x is already 0

        If i is 10 and x is zero, yes, x -= i would have a value of -10. If x was 5 from something else previously, x-=i would end with an x value of -5.

    • EvilHankVenture@lemmy.world
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      1 day ago

      In most languages I’ve seen - is both a unary negation operator and a subtraction operator depending on context. So it would negate an integer literal or a variable in this context.

    • squaresinger@lemmy.world
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      7 hours ago

      Why would they not let you do that? I honestly don’t know a single language that wouldn’t let you do that. Same as basic math notation allows you to do that.

      x = -i

      is a totally valid mathematical equation.

      For the downvoters: Find me a single language that supports operators but doesn’t have an unary minus operator

      • spongebue@lemmy.world
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        13 hours ago

        It’s a valid mathematical notation, sure. But there is an implicit understanding that the - in this case is making a number negative rather than subtracting (or, an implicit subtraction from 0).

        With the way negative numbers generally work in binary there would be much different ones and zeroes stored behind the scenes, so handling that would have to be pretty intentional.

        That said, I did just try it in Java because that’s what I work in normally and I swear I had a gotcha with that. But it worked fine as far as I can tell.

        • squaresinger@lemmy.world
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          7 hours ago

          Find me a language where it doesn’t work like that, and we’ll continue the discussion.

          Unary - operator is standard in every single language that I used so far, including C/C++, Java, Python, Kotlin, Lua, JS/TS, Groovy, PHP, Visual Basic, Excel, Mathematica, Haskell, Bash.

          Here’s more info btw: https://en.wikipedia.org/wiki/Unary_operation

      • squaresinger@lemmy.world
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        7 hours ago

        Works fine in any language I ever used.

        I’m honestly quite surprised that this very basic language feature is even a matter of discussion here.

    • boonhet@sopuli.xyz
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      1 day ago

      Personally I would expect it to behave the same in front of a numeric literal and in front of a variable. I do think most languages do that, but I haven’t actually tested that many and could br wrong.